Water and kerosene are filled in two identical cylindrical vessels both vessel have small hole in two identical cyliendrical rod
Answers
Answered by
5
Consider a wide vessel with a hole in the bottom as shown in the diagram. As the density of the water is greater than the density of the kerosene, it will collect at the bottom.
Let the height of water and kerosene be h1 and h2respectively and their corresponding densities be ρ1 and ρ2
The pressure due to water and kerosene level together would be h1 ρ1 g + h2 ρ2 g
As the water flows from the hole at the bottom of the vessel, there is a kinetic energy involved which is ½ ρ1 v2
Hence, h1 ρ1 g + h2 ρ2 g = ½ ρ1 v2
Divide throughout by ρ1 , we get h1 g + h2 (ρ2 / ρ1) g = ½ v2
Hence, v = [ 2 (h1 + h2 (ρ2 / ρ1) ) g ]1/2
Substituting the values of h1 = 30 * 10-2 m, h2 = 20 * 10-2 m, (ρ2 / ρ1)= 0.80
V = (9.016)1/2 = approximately 3 m/s
Let the height of water and kerosene be h1 and h2respectively and their corresponding densities be ρ1 and ρ2
The pressure due to water and kerosene level together would be h1 ρ1 g + h2 ρ2 g
As the water flows from the hole at the bottom of the vessel, there is a kinetic energy involved which is ½ ρ1 v2
Hence, h1 ρ1 g + h2 ρ2 g = ½ ρ1 v2
Divide throughout by ρ1 , we get h1 g + h2 (ρ2 / ρ1) g = ½ v2
Hence, v = [ 2 (h1 + h2 (ρ2 / ρ1) ) g ]1/2
Substituting the values of h1 = 30 * 10-2 m, h2 = 20 * 10-2 m, (ρ2 / ρ1)= 0.80
V = (9.016)1/2 = approximately 3 m/s
Answered by
0
Answer:
The correct option is A
v1=v2
Given,
Speed of water
(
ρ=1000kg/m³
coming out of hole = v1
Speed of kerosene
(
ρ
=
800
kg/m
3
)
coming out of hole
=
v
2
We know that for small heights of vessels, speed of efflux is independent of density of fluid.
Speed of efflux for small holes,
v=√2gh
which is independent of density.
Similar questions