Physics, asked by PhysicsHelper, 11 months ago

Water and mercury are filled in two cylindrical vessels up to the same height. Both vessels have a hole in the wall near the bottom. The velocity of water and mercury coming out of the holes are v₁ and v₂ respectively.
(a) v₁ = v₂
(b) v₁ = 13.6v₂
(c) v₁ = v₂/13.6
(d) v₁ = √(13.6) v₂

Answers

Answered by brainlycom41
2
v1= v2
THE VELOCITY OF THE WATER V= root (2gh)
which is independent of density of the liquid.
PLS MARK AS BRAINLIST.
Answered by tiwaavi
4

Answer ⇒ Option (a).

Explanation ⇒ Velocity of efflux does not depends upon the nature of the fluid and its density.

We know that the velocity of efflux is given by,

  v = √(2gh)

now, if the height of water and the mercury orifice is same, and g will alredy be same for both.

Then, v₁ = v₂

Hence, Option (a). is correct.

Hope it helps.

Similar questions