Question

water comes out of a hole at the bottom of a tank at 9.8m/s the height of water in the tank is about?
A. 0.5m
b. 5.0m
C 2.5m
D. 1m​

Answer 1

Answer:

This type of problem is solved using the kinetic energy and potential energy conservation principle. It states that the kinetic energy of a rising body is equal to its potential energy at its maximum height.

This type of problem is solved using the kinetic energy and potential energy conservation principle. It states that the kinetic energy of a rising body is equal to its potential energy at its maximum height.The formula for kinetic energy is KE = 1/2 mv^2 and the formula for potential energy is PE = mgh. Equating the two quantities gives

This type of problem is solved using the kinetic energy and potential energy conservation principle. It states that the kinetic energy of a rising body is equal to its potential energy at its maximum height.The formula for kinetic energy is KE = 1/2 mv^2 and the formula for potential energy is PE = mgh. Equating the two quantities givesPE = KE

This type of problem is solved using the kinetic energy and potential energy conservation principle. It states that the kinetic energy of a rising body is equal to its potential energy at its maximum height.The formula for kinetic energy is KE = 1/2 mv^2 and the formula for potential energy is PE = mgh. Equating the two quantities givesPE = KEmgh = 1/2 mv^2

This type of problem is solved using the kinetic energy and potential energy conservation principle. It states that the kinetic energy of a rising body is equal to its potential energy at its maximum height.The formula for kinetic energy is KE = 1/2 mv^2 and the formula for potential energy is PE = mgh. Equating the two quantities givesPE = KEmgh = 1/2 mv^2gh = 1/2 v^2

This type of problem is solved using the kinetic energy and potential energy conservation principle. It states that the kinetic energy of a rising body is equal to its potential energy at its maximum height.The formula for kinetic energy is KE = 1/2 mv^2 and the formula for potential energy is PE = mgh. Equating the two quantities givesPE = KEmgh = 1/2 mv^2gh = 1/2 v^22gh = v^2

This type of problem is solved using the kinetic energy and potential energy conservation principle. It states that the kinetic energy of a rising body is equal to its potential energy at its maximum height.The formula for kinetic energy is KE = 1/2 mv^2 and the formula for potential energy is PE = mgh. Equating the two quantities givesPE = KEmgh = 1/2 mv^2gh = 1/2 v^22gh = v^2h = v^2 / 2g

This type of problem is solved using the kinetic energy and potential energy conservation principle. It states that the kinetic energy of a rising body is equal to its potential energy at its maximum height.The formula for kinetic energy is KE = 1/2 mv^2 and the formula for potential energy is PE = mgh. Equating the two quantities givesPE = KEmgh = 1/2 mv^2gh = 1/2 v^22gh = v^2h = v^2 / 2gh = (9.8 m/s * 9.8 m/s) / (2 * 9.8 m/s^2)

This type of problem is solved using the kinetic energy and potential energy conservation principle. It states that the kinetic energy of a rising body is equal to its potential energy at its maximum height.The formula for kinetic energy is KE = 1/2 mv^2 and the formula for potential energy is PE = mgh. Equating the two quantities givesPE = KEmgh = 1/2 mv^2gh = 1/2 v^22gh = v^2h = v^2 / 2gh = (9.8 m/s * 9.8 m/s) / (2 * 9.8 m/s^2)h = 9.8 m/s / 2 s

This type of problem is solved using the kinetic energy and potential energy conservation principle. It states that the kinetic energy of a rising body is equal to its potential energy at its maximum height.The formula for kinetic energy is KE = 1/2 mv^2 and the formula for potential energy is PE = mgh. Equating the two quantities givesPE = KEmgh = 1/2 mv^2gh = 1/2 v^22gh = v^2h = v^2 / 2gh = (9.8 m/s * 9.8 m/s) / (2 * 9.8 m/s^2)h = 5.0

Answer 2

Concept:

• Mechanical properties of Fluids
• Applying Bernoulli's law
• Daniel Bernoulli developed Bernoulli's principle, which claims that when a flowing liquid or gas moves faster, its internal pressure lowers.
• According to Bernoulli's principle, the total mechanical energy of a moving fluid, which includes the kinetic energy of the fluid's motion as well as the gravitational potential energy of elevation and pressure, remains constant.

Given:

• The velocity of water coming out of the bottom of the tank

Find:

• The height of water in the tank

Solution:

We know that for water coming out of a hole at the bottom of a tank, its speed v

v = √2gh

v^2 = 2gh

h = v^2/2g

v = 9.8 m/s, g = 9.8 m/s^2

h = 9.8^2 /2* 9.8

h = 9.8/2

h = 4.9 m ≈ 5.0 m

The correct option is B.

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