Question

Water drips from a tap at a rate of 4 drops every 3 seconds .Volume of one drop of water is 0.4 cubic cm. The dripped water is collected in a cylindrical vessel.The outer diameter and uniform thickness of this vessel is 10 cm and 1 cm respectively. How many minutes will be required to fill the vessel completely if it's height is 70 cm?

Answer 1

Total minute to fill vessel  = 109.95 minute.

Given:

• Water drips from a tap at a rate of 4 drops every 3 seconds .
• Volume of one drop of water is 0.4 cubic cm.
• The outer diameter  of this vessel is 10 cm.
• Uniform thickness of this vessel is 1 cm.
• Height of this vessel is 70 cm.

Find:

      How many minutes will be required to fill the vessel completely.

Explanation:

• Inside diameter of the vessel is 2 times less than thickens of the vessel because of both side thickness
• Inside diameter of the vessel = 10 - (2×1)

                                                         =8 cm.

• Volume of vessel = $\frac{\pi }{4}$ ×(Inside diameter) ² × Height

                                      = $\frac{\pi }{4}$ × 8² × 70

                                     =3518.58 cm³

• 4 drops every 3 seconds and one drop =0.4 cm³
• Therefore 4 drop = 4 × 0.4 = 1.6 cm³ for 3 second.
• Therefore for 1 minutes total volume fill will be =1.6 ×$\frac{60}{3}$

                                                                                     = 32 cm³

• Total minute to fill vessel = $\frac{3518.58}{32}$

                                                  = 109.95 minute.

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