Question

Water drops are falling in regular intervals of time from top of a tower of height 9 m 1' 4 drop begins
& 3 drops from the top of the tower
to fall when 1" drop reaches the ground, find the positions of 2
107​

Answer 1

Answer:

2nd & 3rd drop 5 & 8 m above ground

2nd & 3rd drop 4 & 1 m  from top of tower

Explanation:

Water drops are falling in regular intervals of time from top of a tower of height 9 m

If 4th drop begins to fall when 1st drop reaches the ground, find the position of the 2nd and 3rd drop from the top of the tower.

Let say at  t = 0 1st drop fall

Let say t is the interval

2nd drop fall at t

3rd drop fall at 2t

4th drop fall at 3t

it means 1st drop reaches ground in 3t

S = ut + (1/2)at²

u = 0   t = 3t   a = g  S = 9

9 = (1/2)g (3t)²

=> t²g = 2

2nd drop traveled for 3t - t = 2t

S = (1/2)g(2t)² = 2t²g  = 2*2 = 4 m

Distance covered = 4 m height from ground = 9-4 = 5 m

3rd drop traveled for 3t - 2t = t

S = (1/2)g(t)² = t²g/2  = 2/2 = 1 m

Distance covered = 1 m  height from ground = 9-1 = 8 m

2nd & 3rd drop 5 & 8 m above ground

2nd & 3rd drop 4 & 1 m  from top of tower