Water drops are falling regularly at a constant interval of 1s from a tap. If the total time taken by a drop to strike the ground is 5s, find the distance between the 2nd and the 3rd drop when the 1st drop hits the ground?
Take g= 10m/s^2
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Answer:
35 m
Explanation:
Given Water drops are falling regularly at a constant interval of 1 s from a tap. If the total time taken by a drop to strike the ground is 5 s, find the distance between the 2nd and the 3rd drop when the 1st drop hits the ground?
We are given water drops at an interval of 1 s from a tap. It will be 5s to strike the ground and initial velocity u is zero.
So distance travelled by the first drop will be
S = ut + 1/2 gt^2
S = 1/2 gt^2 (since u = 0)
S = 1/2 x 10 x 5^2
S = 125 m
Now for 2nd drop will be
S = 1/2 gt^2
S = 1/2 x 10 x 4^2
S = 80 m
Again for the 3rd drop we have
S = 1/2 gt^2
S = 1/2 x 10 x 3^2
S = 45 m
Therefore distance between 2nd and 3rd drop will be
80 - 45 = 35 m
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