Question

Water drops fall at regular intervals from roof .At an instant ,when a drop is about to leave the roof ,the height through which 3 successive drops have fallen are in the ratio

Answer 1

Answer:

Supplier this regular interval is 1 sec

then

t = 0 sec first drop

t = 1 sec second drop

t = 2 sec III rd drop

t=3secIV

th

second

⇒ position of first drop below the roof will be

h

1

=

2

1

9(3)

2

=

2

99

position of second drop below the roof will be

h

2

=

2

1

9(3−1)

2

=

2

49

separation=h

2

−h

1

=

2

59

position of III rd drop

h

3

=

2

1

9(3−2)

2

=

2

9

⇒separation=h

3

−h

2

=

2

39

Potion of IV

th

drop is h

4

=0⇒

separate=h

4

−h

3

=

2

9

ratio = 1:3:5