Question

Water drops fall from a tap at a height h above the ground. The drops fall at regular intervals
of time. When the first drop touches the ground, fifth drop is ready to fall. Then separation
between the second and third drops as
please answer fast....​

Answer 1

Explanation:

Height of tap = 5m and (g) = 10m/sec

For the first drop, 5=ut+gt

 =(0×t)+×10t  

2v

=5t  

 or t  =1 or t=1.

It mean that the third drop leaves after one second of the first drop. Or, each drop leaves after every 0.5 sec.

Distance covered by the second drop in 0.5 sec.

=(0.5)

=1.25m

Therefore, distance of the second drop above the ground

=5−1.25=3.75m