Question

Water drops fall from a tap at an interval of 1 s. What is the distance between the 3rd and 4th drop

when the 7th drop just leaves?​

Answer 1

Answer:

$\huge\color{pink}\boxed{\colorbox{Black}{❥ Answer}}$

Water drops from a tap at a 1 second interval. What is the distance between the 3rd and 5th drop when the 6th drop is just coming from it?

Two seconds after that the 5th drop falls, and one second after that we need to know the distance between the 3rd and 5th drop.

This means that we need to calculate the distance of drop 3 after 3 seconds of falling, and drop 5 after it has fallen for 1 second, and find the difference in the computed distances.

Ok: Now we can use our basic physics equations:

For the 3rd drop:

z3(t = 3 second) = 1/2 (9.81 m/s^2)(3 s)^2 = 44.15 m

For 5th drop:

z3(t = 1 second) = 1/2 (9.81 m/s^2)(1 s)^2 = 4.91 m

So the distance between them is:

S = |z3 - z5| = |44.15 m - 4.91m| (Note absolute value | x |)

S = 39.25 m approximately

Answer 2

$\huge\color{pink}\boxed{\colorbox{Black}{❥ Answer}}$

Water drops from a tap at a 1 second interval. What is the distance between the 3rd and 5th drop when the 6th drop is just coming from it?

Two seconds after that the 5th drop falls, and one second after that we need to know the distance between the 3rd and 5th drop.

This means that we need to calculate the distance of drop 3 after 3 seconds of falling, and drop 5 after it has fallen for 1 second, and find the difference in the computed distances.

Ok: Now we can use our basic physics equations:

For the 3rd drop:

z3(t = 3 second) = 1/2 (9.81 m/s^2)(3 s)^2 = 44.15 m

For 5th drop:

z3(t = 1 second) = 1/2 (9.81 m/s^2)(1 s)^2 = 4.91 m

So the distance between them is:

S = |z3 - z5| = |44.15 m - 4.91m| (Note absolute value | x |)

S = 39.25 m approximately