Question

Water drops fall from a tap at height h above the ground. The drops fall at a regular intervals of time when the first drop touches the ground fifth drop is ready to fall. The separation between 2nd and 3rd drop is

Answer 1

Answer:

Height of tap = 5m and (g) = 10m/sec2

For the first drop, 5=ut+gt2

=(0×t)+×10t2v=5t2 or t2=1 or t=1.

It mean that the third drop leaves after one second of the first drop. Or, each drop leaves after every 0.5 sec.

Distance covered by the second drop in 0.5 sec.

=(0.5)2=1.25m

Therefore, distance of the second drop above the ground

=5−1.25=3.75m