Question

Water drops fall from rest from a nozzle from a height of omat regular interval ottime such that the first
drop reaches the ground when sixth drop is released from the nozzle. The height of the fourth on
from the ground is g = 10 ms )
a) 3.2m
b) O.S m
) 1.m
d) *2m
harani
mshels is deached from the bo​

Answer 1

Answer:

Height

Time period to reach ground

$t = \sqrt{ \frac{2 \times 5}{g} } = 1 \: \: secs$

So in 1 second 6 drops fall , so time interval between two drops is 1/5 . And let if first drop is dropped at t = 0 ,then 4th drop was dropped after 3 × 1/5 = 0.6 secs , now it is 1 so that drop has travelled for 0.4 Secs .

Initial velocity zero

$s = ut + \frac{1}{2} g {t}^{2} \\ s = \frac{1}{2} \times 10 \times (0.4) {}^{2} =0 .8 \: m$

So height is 5 - 0.8 = 4.2 m