Question

Water drops fall regular Lee from height 180 cm above the ground the first drop striking to the ground then fourth drop begins to fall what is the position of second drop from the tap

Answer 1

Answer:

the position of second drop from the tap is 80 m

Explanation:

Water drops fall regularly from height 180 cm

U = 0

S = 180 m

a = g = 10 m/s

Time taken to reach ground = t

using S = ut + (1/2)at²

180 = 0 + (1/2)10 t²

=> t = 6

after 6 sec forth drop begin to fall

=> Every drop falls every 2 sec

=> 2nd Drop has travelled for 4 sec

the position of second drop from the tap is the distance travelled

(1/2)10 * 4²  = 80 m

the position of second drop from the tap is 80 m