Question

Water drops falls at regular intervals from a tap which is 8 m
above the ground. The third drop is leaving the tap at the
instant the first drop touches the ground the second drop at
that instant, is at height:
a. 2 m
b. 6 m
c. 4 m
d. 6.05 m​

Answer 1

Answer:

Height of tap = 5m and (g) = 10m/sec

2

For the first drop, 5=ut+gt

2

=(0×t)+×10t

2v

=5t

2

or t

2

=1 or t=1.

It mean that the third drop leaves after one second of the first drop. Or, each drop leaves after every 0.5 sec.

Distance covered by the second drop in 0.5 sec.

=(0.5)

2

=1.25m

Therefore, distance of the second drop above the ground

=5−1.25=3.75m