Question

Water enters a pipe of diameter 3.0cm with a velocity of 3.0m/s. The water encounters a construction where it's velocity is 12m/s. What is the diameter of the constricted portion of the pipe

Answer 1

Answer:

Explanation:

hope it ll help

Answer 2

Answer:

1.5 cm

Explanation:

formula

A1 V1 = A2 V2

here A =

$a1v1 = a2v2$

$here \: \\ a = \pi {d}^{2} \div 2$

$now \\( \pi {d1}^{2} \times v1) \div 2 = (\pi {d2}^{2} \times v2 )\div 2$

${d2 }^{2} = ({d1}^{2} \times v1) \div v2$

$({d1}^{2} \times v1) = ( {d2}^{2} \times v2)$

now put value

d1= 3 cm

v1 = 300 cm/s

v2 = 1200 cm/s