Water enters through end A with a speed v1 and leaves through end B with a speed v2 of a cylindrical tube AB. The tube is always completely filled with water. In case I the tube is horizontal, in case II it is vertical with the end A upward and in case III it is vertical with the end B upward. We have v1 = v2 for
(a) case I
(b) case II
(c) case III
(d) each case
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(d) each case
Explanation:
- As per the equation of continuity, the amount of water that crosses point A over some amount of time is equal to the amount that crosses the point B.
- Which means, AAV1 =ABV2
- [AA and AB are area at the points of A and B respectively
- V1 and V2 are velocity of water at the points of A and B respectively]
- So, in the cylindrical tube AB the velocity of water entering into point A and leaving through point B is equal (V1 =V2) as the cross-sectional area at both points are same (AA =AB) for all the three cases.
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