Water expands when if freezes. Determine amount of work done in joules, when a system consisting of 1.0 L of liquid water freezes under a constant pressure of 1.0 atm and forms 1.1 L of ice.
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Answer:The workdone =−P[ext]dV=−PΔV
Vfinal=Volume of ice=1.1 L
Vinitial=Volume of water=1.1 L
ΔV=Vfinal−Vinitial=1.1−1.0=0.1 L
Workdone=−PΔV=−[1.0×0.1]=−0.1 L atm=−10.1 J (1 L atm=101.32J)
Explanation:
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