Question

water falls from a height of 20 m with a rate of 100kg/s. how many calorie of heat produced per sec on a striking the earth? assume whole energy converted into heat

Answer 1

4689 calorie of heat produced per sec on a striking the Earth.

Explanation:

=> It is given that,

mass per sec = 100kg/s

height, h = 20 m

Acceleration of gravity, g = 9.8 m/s²

=> So, Loss in potential energy (ΔPE) of water on striking the Earth per second:

ΔPE = mass/sec * g * h

       = 100 * 9.8 * 20

       = 19600 J

=> As per the question, assume whole energy converted into heat:

4.18 J is equal to One calorie,  then heat generated from 19600 J in calorie

= 19600*1 / 4.18

= 4,688.99

≈ 4689 cal

Hence, 4689 calorie of heat produced per sec on a striking the Earth.

Learn more:

Q:1 A ball of mass 200 g falls from a height of 5 mtr.What is the kinetic energy when it just reaches the ground(g=9.8metres per second square)

Click here : https://brainly.in/question/200610

Q:2 An iron ball falls from a height of 1 km of the ground. If all the energy is converted into heat, the rise in temperature of the ball will be (sp. heat of iron=0.1)

Click here: https://brainly.in/question/46094

Answer 2

Solution -

• h = 20 m
• m = 100 kg
• g = 9.8 m/s²

On reaching ground the kinetic energy will change into potential energy.

hence ,

Q = mgh

Q = 100×9.8×20

Q = 19600 J

In kcal

$\sf \:Q \: = \dfrac{19600}{4.18 \times {10}^{3} }$

Q = 4.68 Kcal or 4.7 kcal (approx)