water falls from a height of 20 m with a rate of 100kg/s. how many calorie of heat produced per sec on a striking the earth? assume whole energy converted into heat
Answers
4689 calorie of heat produced per sec on a striking the Earth.
Explanation:
=> It is given that,
mass per sec = 100kg/s
height, h = 20 m
Acceleration of gravity, g = 9.8 m/s²
=> So, Loss in potential energy (ΔPE) of water on striking the Earth per second:
ΔPE = mass/sec * g * h
= 100 * 9.8 * 20
= 19600 J
=> As per the question, assume whole energy converted into heat:
4.18 J is equal to One calorie, then heat generated from 19600 J in calorie
= 19600*1 / 4.18
= 4,688.99
≈ 4689 cal
Hence, 4689 calorie of heat produced per sec on a striking the Earth.
Learn more:
Q:1 A ball of mass 200 g falls from a height of 5 mtr.What is the kinetic energy when it just reaches the ground(g=9.8metres per second square)
Click here : https://brainly.in/question/200610
Q:2 An iron ball falls from a height of 1 km of the ground. If all the energy is converted into heat, the rise in temperature of the ball will be (sp. heat of iron=0.1)
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Solution -
- h = 20 m
- m = 100 kg
- g = 9.8 m/s²
On reaching ground the kinetic energy will change into potential energy.
hence ,
Q = mgh
Q = 100×9.8×20
Q = 19600 J
In kcal
Q = 4.68 Kcal or 4.7 kcal (approx)