Question

Water falls from a height of 50m. Calculate the rise in temperature of water when it strikes the bottom, g=10m/s2 specific heat capacity of water = 4200j/kg/C

Answer 1

We can take that work done is equal
So,
mgs=mc∆t
therefore
∆t=gs/c
g=10,s=50,c=4200
answer ∆t=0.119 °C

Answer 2

Answer:

The temperature of water rises about 0.12 degree C when it strikes the bottom.

Explanation:

The water fallen gains temperature and strikes bottom with an increased temperature, calculated as follows –

Given that the height of fall h = 50 m

Acceleration g = 10 m/ s 2

Let the water falling has a mass of m.

Thereby, the energy of water E is given by –

E = m g h

E = m x 10 x 50

E = 500 m

Now this is the amount of energy which is converted to the heat causing the rise in temperature, so we have –

E = δQ

E =δQ  

E = m s δ T

Given s is the specific heat capacity of water as s = 4200 j / kg / C

E = m s δT

500 m = m 4200 δ T

δ T = 500 / 4200

δ T = 5 /42

δT = 0.12 degree C.