Water falls from a height of 50m. Calculate the rise in the temperature of water when it strikes the bottom
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Assume the mass of water = m
Height of water h = 50 m
g = 10 m/s2
Energy of water (E) = mgh
= m (10) (50)
E = (500 m) J ...(i)
This amount of energy is converted into heat
E = ΔQ
E = msΔT ...(ii)
Also, s = 4200 J/(kg –°C)
From equation (i) and (ii)
=500m=ms∆t
=∆T=500\s=500/4200
=0.12 degree Celsius (ans)
Height of water h = 50 m
g = 10 m/s2
Energy of water (E) = mgh
= m (10) (50)
E = (500 m) J ...(i)
This amount of energy is converted into heat
E = ΔQ
E = msΔT ...(ii)
Also, s = 4200 J/(kg –°C)
From equation (i) and (ii)
=500m=ms∆t
=∆T=500\s=500/4200
=0.12 degree Celsius (ans)
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