Question

Water filled in an empty tank of area 10 A through a tap of cross sectional area A. The speed of water flowing out of tap is given by v(m/s)=10(1-sin((pi)/(30)t) where t is in second. The height of water level from the bottom of the tank at t=15 second will be:

Answer 1

Answer:

Explanation:

Q t=AV t,

10 A=[1-sin(πt/30)],

V=10A[t+cosπt/30//π/30],

V=10 A[15+cosπ/2//π/30-0-cos0//π/3],

V=10A[15-30/π],

h=V/10 A,

[15-30/π] is the heigth of the tank.

Hope it helps and sorry if you didn't understand,but the answer is correct.