Question

Water flow along a horizontal pipe of which the cross-
section is not uniform. The pressure is 30mm of Hg where
the velocity is 0.02 m/s. Find the pressure at a point where
the velocity is 1.2 m/s.​

Answer 1

Answer:

Given :

P₁ = 30 mm of Hg

= > 3 cm of Hg = 3 × 13.6 × 980

ρ₁ = 13.6 g / cc

V₁ = 0.20 m / sec

We are asked to find P₂ :

From Bernoulli's theorem we know :

ρ₁ + 1 / 2 ρ V₁² = ρ₂ + 1 / 2 ρ V₂²

= > On solving further we get :

ρ₂ = 3298 dyne / cm²

= > 32984 / ( 13.6 × 980 )

ρ₂ = 2.475 cm of Hg

Therefore , pressure at a point where velocity 1.2 m / sec is 2.475 cm of Hg

Answer 2

$\large \underline{ \red{ \boxed{ \bf \pink{Answer}}}}$