Question

Water flowed out of a tank at a steady rate. A total of 18 and one-half gallons flowed out of the tank in 4 and one-fourth hours. Which expression determines the quantity of water leaving the tank per hour?

Answer 1

Answer:

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Answer 2

Answer:

Question:-

Water flowed out of a tank at a steady rate. A total of $18\frac{1}{2}$ gallons flowed out of the tank in $4 \frac{1}{4}$ hours. Which expression determines the quantity of water leaving the tank per hour?

a) $\frac{17}{4}$ × $\frac{36}{2}$

b) $\frac{38}{2}$ × $\frac{17}{4}$

c) $\frac{4}{17}$ × $\frac{37}{2}$

d) $\frac{37}{2}-\frac{17}{4}$

Answer:-

Therefore, c) $\frac{4}{17}$ × $\frac{37}{2}$ is the expression that determines the quantity of water leaving the tank per hour.

Hence, the water leaving the tank per hour is $4\frac{6}{17}$ gallons.

Step-by-step explanation:

Given:-

• Water flowed out of the tank = $18\frac{1}{2}$ gallons

                                                         = $\frac{37}{2}$ gallons

• Time taken = $4 \frac{1}{4}$ hours

                           =  $\frac{17}{4}$ hours

Therefore, $\frac{37}{2}$ gallons of water flowed out of the tank in  $\frac{17}{4}$ hours.

So, water flowed out of the tank per hour =  $\frac{37}{2}$ ÷  $\frac{17}{4}$

                                                                     =  $\frac{37}{2}$ × $\frac{4}{17}$

                                                                     = $\frac{148}{34}$

                                                                     = $\frac{74}{17}$

                                                                    = $4\frac{6}{17}$ gallons.

Hence, the water leaving the tank per hour is $4\frac{6}{17}$ gallons.

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