Question

Water flowing at the rate of 0.7m/s through a circular pipe whose internal diameter is 2 cm into a cylindrical tank , the radius of whose base is 40 cm . Determine the increase in level of water in an hour

Answer 1

Cylindrical pipe:-
Internal diameter = 2cm
Internal radius = 1cm
Rate of flow of water in 1sec = 0.7m/sec
= 70cm/sec [1m=100cm]

Volume of water flow in one sec = 22/7*1*1*70
Volume of water flow in one hour= 22/7*1*1*70*3600 [1 hour=60*60se=3600sec]

Now, Volume of water flow in one hour in cylindrical pipe = Volume of water in the cylindrical container.

22/7*1*1*70*3600 = 22/7*40*40*h
22/7*1*1*70*3600÷22/7*40*40 = h

H = 157.5cm---->answer

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