Question

water flowing at the rate of 15 km per hour through a pipe of diameter 14 cm into a rectangular tank which is 50 M long and 44 M wide find the time in which level of the water in the tank will rise by 21 CM

Answer 1

Answer:

Let the level of water in the pond rises by 21 cm in t hours.

Speed of water = 15 km/hr

Diameter of the pipe = 14/100 m

Radius of the pipe (r) = 7/100 m

Volume of water flowing out of the pipe in 1 hour

= π r 2 h

= (22/7) x (7/100) x (7/100) x 15000

= 231 m3

Volume of water flowing out of the pipe in t hours = 231 t m3.

Volume of water in the cuboidal pond

= 50 x 44 x (21/100)

= 462 m3

Volume of water flowing out of the pipe in t hours = Volume of water in the cuboidal pond

So, 231 t = 462

t = 2

Thus, the required time is 2 hours.

Answer 2

$\it\huge\mathfrak\red{Answer:-}$]

Let the level of water in the pond rises by 21 cm in t hours.

$\it\huge\mathfrak\red{Given:-:-}$]

Speed of water = 15 km/hr

Diameter of the pipe = 14/100 m

Radius of the pipe (r) = 7/100 m

$\it\huge\mathfrak\red{Solution:-:-}$]

Volume of water flowing out of the pipe in 1 hour

= π r 2 h

= (22/7) x (7/100) x (7/100) x 15000

= 231 m3

Volume of water flowing out of the pipe in t hours = 231 t m3.

Volume of water in the cuboidal pond

= 50 x 44 x (21/100)

= 462 m3

Volume of water flowing out of the pipe

in t hours = Volume of water in the cuboidal pond

So, 231 t = 462

$\huge\boxed{\texttt{\fcolorbox{red}{white}{2 Hours}}}$

$<marquee>$]

Thus, the required time is 2 hours.