Water flowing through two horizontal pipes of different diameters which are connected together. In the first pipe the velocity of water is 4m/s and pressure is 2×10^4N/m^2. Calculate the velocity and pressure of water in the second pipe. The diameters of the pipe are 3cm and 6cm respectively. The density of water is 10^3kg/m^3.
Answers
Answered by
0
Answer:
when the two pipes are in horizontal in different diameters which is connected
given,
- first pipe velocity = 4 m/s & p =2× 10^4 N/m^2
- diameters of two pipes are 3cm & 6cm
- u should find the remaining answer with help of formula
Answered by
0
Answer:
From continuity equation,
A
1
v
1
=
A
2
v
2
⇒
v
1
v
2
=
A
2
A
1
A
2
&
v
2
represents the cross-sectional area and velocity in the wider tube.
If
d
=
diameter of pipe, then
A
∝
d
2
⇒
v
1
v
2
=
d
2
2
d
2
1
∵
v
1
=
4
m/s
⇒
4
v
2
=
6
2
3
2
∴
v
2
=
4
×
3
2
6
2
=
1
m/s
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