Physics, asked by Tekin321, 10 months ago

Water flowing through two horizontal pipes of different diameters which are connected together. In the first pipe the velocity of water is 4m/s and pressure is 2×10^4N/m^2. Calculate the velocity and pressure of water in the second pipe. The diameters of the pipe are 3cm and 6cm respectively. The density of water is 10^3kg/m^3.

Answers

Answered by vishal2260
0

Answer:

when the two pipes are in horizontal in different diameters which is connected

given,

  • first pipe velocity = 4 m/s & p =2× 10^4 N/m^2
  • diameters of two pipes are 3cm & 6cm
  • u should find the remaining answer with help of formula
Answered by rtarunraj29
0

Answer:

From continuity equation,

A

1

v

1

=

A

2

v

2

v

1

v

2

=

A

2

A

1

A

2

&

v

2

represents the cross-sectional area and velocity in the wider tube.

If

d

=

diameter of pipe, then

A

d

2

v

1

v

2

=

d

2

2

d

2

1

v

1

=

4

m/s

4

v

2

=

6

2

3

2

v

2

=

4

×

3

2

6

2

=

1

m/s

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