water flows along a pipe of radius 0.6 cm at 8 cm per sec this pipe is draining the water from a tank which holds 1000 liter of water when full how long would it take to completely empty the tank?
Answers
Answered by
64
In one second, the volume of water that flows out = Area of cross-section of the pipe x distance traveled in one second
= 22/7 x 0.6² x 8 = 9.05 cm³
Volume of the tank = 1000 liters
1 liter = 1000cm³
Volume of tank = 1000 x 1000 cm³ = 1000000cm³
Time taken to empty the tank = 1000000/9.05
= 1104797 seconds
= 110479/3600 hours
= 30.694 hours
= 22/7 x 0.6² x 8 = 9.05 cm³
Volume of the tank = 1000 liters
1 liter = 1000cm³
Volume of tank = 1000 x 1000 cm³ = 1000000cm³
Time taken to empty the tank = 1000000/9.05
= 1104797 seconds
= 110479/3600 hours
= 30.694 hours
Answered by
15
Answer:
volume of pipe=πr^2h
=22/7×0.6×0.6×8
=9.05
volume of tank=1000litre
1 litre=1000cm^3
1000 litre=1000×1000
=1000000cm^3
time taken to empty the tank=1000000/9.05
=1104797seconds
=110479/3600 [1sec=3600hours]
=30.69hours
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