Water flows at the rate of 4 liter per second through an
orifice at the bottom of lake which contains water 720 cm
deep. Find the rate of escape of water if additional perssure
of 16 kg/cm² is applied at the surface of water.
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Answer:
Given :
h = 720 cm
V = √ ( 2 g h )
V = √ ( 2 × 980 × 720 )
V = 4 litres / sec
Additional pressure = 16 kg / cm² = 16000 g / cm²
Now :
16000 g / cm² = ( 16000 × 980 ) / ( 980 ) cm of water
= > 16000 cm of water .
Pressure head = h₁ = 16000 + 720 = 16720 cm
New velocity :
v₁ = √ ( 2 g h₁ )
v₁ = √ ( 2 × 980 × 16720 )
V = a v₁ and V₁ = a v₁
= > V₁ = V ( v₁ / v )
V₁ = √ ( 16720 / 720 )
V₁ = √ ( 1672 / 72 ) litres / sec
V₁ = 19.28 litres / sec
Therefore , rate of escape of water is 19.28 litres / sec
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