Question

water flows from three pipes in a pool .first 2 pipes together takes the same time to fill the pool as the third pipe alone takes .the second pipe fills the pool 5 hours faster than the first pipe alone and 4 hours slower than the third pipe. find the time required by each 5 to fill the pool independently?

Answer 1

Let the volume of the pool = V

Let the time taken by second pipe to fill the pool = x hours

time taken by first pipe to fill the pool = (x+5) hours,

and time taken by third pipe to fill the pool = (x-4) hours.

In One hour,

First pipe can fill parts of volume of pool = V/x+5

Second pipe can fill parts of volume of pool =V/x

Third pipe can fill parts of volume of pool =V/x-4

Now, It is given that,

Time taken by first and second pipe simultaneously = Time taken by third pipe alone





Neglect the negative value.

Thus, the time taken by second pipe to fill the pool = x hours=10 hours.

time taken by first pipe to fill the pool = (x+5) hours= 10+5=15 hours.

time taken by third pipe to fill the pool = (x-4) hours=1-4=6 hours.