Question

Water flows in a horizontal tube as shown in figure. The pressure of water changes by 600 N/m between A
and B where the area of cross-section are 30 cm2 and 15 cm? respectively. Find the rate of flow of water
through the tube.
​

Answer 1

The rate of the flow is 1890 cm^3 /s

Explanation:

Let the velocity at A=vA

and at point B= vB

By the equation of continuity vB / VA= 30cm^2 / 15cm^2= 2  cm^2

By Bernoulli equation

PA+1 / 2ρv^2A = PB+1 / 2ρv^2B

or

PA−PB = 1 /2ρ(2vA)^2 −  1 / 2ρv^2A =3 / 2ρv^2A

vA^2 = √0.4ms^2 = 0.63 ms^-1

The rate of flow= (30cm^2)(0.63ms^-1)

                         =1890 cm^3 /s

Thus the rate of the flow is 1890 cm^3 /s

Also learn more

Difference between speed and velocity?

https://brainly.in/question/4637948