water flows in a rectangle tank 60m and 40m broad at the Base through the pipe whose cross section is 20cm^2 at the speed of 12 km per hour. how much the level of water rises in tank in 30 minutes?
Answers
Answer:
Volume of water added = area of cross section × increase in height
=30×20×1m^3
=600m^3
Area of cross section of pipe=0.05×0.05 m^2
=0.0025m^2
Let the speed of water flow be x m per hour.
Now ,
Volume added= area of cross section× speed ×time
Or 600 m^3 = 0.0025 m^2 × 8 hr. x m/ hr.
Or x= 600÷(0.0025×8)
Or x=600÷0.02
Or x= 30000
Hence speed = 30000 m/ hr.
=30km/hr.
Step-by-step explanation:
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Answer:
Volume of water added = area of cross section × increase in height
=30×20×1m^3
=600m^3
Area of cross section of pipe=0.05×0.05 m^2
=0.0025m^2
Let the speed of water flow be x m per hour.
Now ,
Volume added= area of cross section× speed ×time
Or 600 m^3 = 0.0025 m^2 × 8 hr. x m/ hr.
Or x= 600÷(0.0025×8)
Or x=600÷0.02
Or x= 30000
Hence speed = 30000 m/ hr.
=30km/hr.