Question

water flows in a rectangle tank 60m and 40m broad at the Base through the pipe whose cross section is 20cm^2 at the speed of 12 km per hour. how much the level of water rises in tank in 30 minutes?​

Answer 1

Answer:

Volume of water added = area of cross section × increase in height

=30×20×1m^3

=600m^3

Area of cross section of pipe=0.05×0.05 m^2

=0.0025m^2

Let the speed of water flow be x m per hour.

Now ,

Volume added= area of cross section× speed ×time

Or 600 m^3 = 0.0025 m^2 × 8 hr. x m/ hr.

Or x= 600÷(0.0025×8)

Or x=600÷0.02

Or x= 30000

Hence speed = 30000 m/ hr.

=30km/hr.

Step-by-step explanation:

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Answer 2

Answer:

Volume of water added = area of cross section × increase in height

=30×20×1m^3

=600m^3

Area of cross section of pipe=0.05×0.05 m^2

=0.0025m^2

Let the speed of water flow be x m per hour.

Now ,

Volume added= area of cross section× speed ×time

Or 600 m^3 = 0.0025 m^2 × 8 hr. x m/ hr.

Or x= 600÷(0.0025×8)

Or x=600÷0.02

Or x= 30000

Hence speed = 30000 m/ hr.

=30km/hr.