Question

Water flows out of a big tank along AB of length L and radius r and bent at right angles at other end as shown in the figure.

The rate of flow is Q m3/s. Calculate moment of force exerted by water on tube about A

Answer 1

We know that,

Q = AV

But A = πr^2

So, V = Q/πr^2

Force = pAV^2 , p = density of water

Force = p(AV)V

We know AV = Q and V = Q/πr^2

So, Force = p x Q x Q/πr^2

Since , length is not negligible here,
Force = pQ^2l/ πr^2

Hope This Helps You!

Answer 2

Heya....

===== Answer =======

Q = AV

Where, A= πr^2
V = Q/πr^2

Force is :- pAV^2 , p is density of water...

We know that,,

Force is ,, P(AV)V
AV = Q , V = Q/πr^2

Then final force will be --

P X Q X Q/πr^2

Lenght will not estimated here,, so...answer will be --

PQ^2 / πr^2 ...

Thank you