Math, asked by guptasakshi9109, 1 year ago

Water flows out through a circular pipe of internal diameter 1 cm at the rate of 18 cm per second into an empty

Answers

Answered by sashanksaimanikanta
3

Solution:

Given, radius of tank, r1 = 40 cm

Let height of water level in tank in half an hour = 1 cm.

Also, given internal radius of cylindrical pipe, r2 = 1 cm

and speed of water = 80 cm/s i.e., in 1 water flow = 80 cm

In 30 (min) water flow = 80x 60 x 30 = 144000 cm According to the question,

Hence, the level of water in cylindrical tank rises 90 cm in half an hour.

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