Water flows out through a circular pipe whose internal diameter is 2 centimetre at the rate of 6 metre per second into a cylindrical tank the radius of whose base is 60 cm find the rise in the level of water in 30 minutes
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The volume of the water that flows out through the circular pipe of radius 1cm, at the rate of 6 metres per second, in one second is same as the volume of a cylinder of radius 1cm and height=6 metres.
Therefore,
volume of the water that flows out through the circular pipe in 1 second=
2 3
22/7 × (1/100) × 6m
=> volume of the water that flows out through the circular pipe in 30 minutes
3
22/7 × 1/10000×6×30×60m
let the water level rise to a height of 'h' metres in 30 minutes in the cylindrical tank of base radius 60cm. Then,
Volume of the water collected in the tank in 30 minutes=
2
22/7 × (60/100) × h
Therefore,
2
22/7×(60/100)×h= 22/7×1/10000×6×30×60
=> 3 m
Therefore,
volume of the water that flows out through the circular pipe in 1 second=
2 3
22/7 × (1/100) × 6m
=> volume of the water that flows out through the circular pipe in 30 minutes
3
22/7 × 1/10000×6×30×60m
let the water level rise to a height of 'h' metres in 30 minutes in the cylindrical tank of base radius 60cm. Then,
Volume of the water collected in the tank in 30 minutes=
2
22/7 × (60/100) × h
Therefore,
2
22/7×(60/100)×h= 22/7×1/10000×6×30×60
=> 3 m
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Answer:
Answer is 3 m
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