Water flows out through a circular pipe whose internal radius is 1 cm at the rate of 80 cm/sec into an empty cylindrical tank, the radius of whose base is 40 cm. By how much will the level of water rise in the tank in half an hour?
Answers
Answered by
6
Radius of pipe=1cm.
height or length of pipe in 1second=80cm
volume of water in pipe in 1 second= πr^2h
=π1*1*80
=π80
radius of cylinderical tank=40 cm
height= h cm
volume of tank= π40*40*h
Time= 30minutes =1800 seconds
1800*π*80=π*40*40*h
h=1800*80/40*40
h= 90 cm
Therefore, water will rise to a height of 90 cm in 30 minutes...
height or length of pipe in 1second=80cm
volume of water in pipe in 1 second= πr^2h
=π1*1*80
=π80
radius of cylinderical tank=40 cm
height= h cm
volume of tank= π40*40*h
Time= 30minutes =1800 seconds
1800*π*80=π*40*40*h
h=1800*80/40*40
h= 90 cm
Therefore, water will rise to a height of 90 cm in 30 minutes...
Similar questions