Question

Water flows out through a circular pipe whose internal diameter is 2 cm at the rate of 0.8 m/s into a cylindrical tank, the radius of whose base is 40 cm. By
how much will the level rise in one and a half hour?​

Answer 1

Answer:

3 cm

Step-by-step explanation:

Internal diameter of the pipe =2cm

So its radius =1cm=

100

1

m

Water that flows out through the pipe in 6ms

−1

So volume of water that flows out through the pipe in 1sec=π×

100

1

2

×6m

3

∴ In 30 minutes, volume of water flow =π

100×100

1

×6×30×60m

3

This must be equal to the volume of water that rises in the cylindrical tank after 30 minutes and height up to which it rises say h.

Radius of tank =60cm=

100

60

m

Volume =π(

100

60

)

2

h

=π(

100

60

)

2

h=π×

100×100

1

×6×30×60

⇒

100×100

60×60

h=

100×100

6×30×60

⇒h=

36

3×36

=3m

So required height will be 3m

Hope it helps.

Mark as BRAINLIEST ANSWER.

Answer 2

Answer:

3m

Step-by-step explanation

Internal diameter of the pipe =2cm

So its radius =1cm=

100

1

m

Water that flows out through the pipe in 6ms

−1

So volume of water that flows out through the pipe in 1sec=π×

100

1

2

×6m

3

Hope its help you ✅ ✅ ✅

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