Question

Water flows out through a circular pipe whose internal diameter is 2 cm, at the rate of 6 metres per second into a cyclindrical tank, the radius of whose base is 60 cm. by how much will the level of water rise in 30 minutes?

Answer 1

Hi there!
Here's the answer:

•°•°•°•°•°<><><<><>><><>°•°•°•°•°•°

Given
Internal Diameter = 2 Cm
Internal Radius = 1 Cm

Rate = 6 m/s (=>6 m In 1 sec)

30 minutes = 30 × 60 = 1800 sec


10800 m in 1800 sec

Volume of Circular pipe = Volume of Cylindrical tank


$Volume = Πr^{2}h$
=> $Π×1×1×10800 = Π×60×60×h$
=> $h = \frac{10800}{3600}$
=> h = 3m


•°• Water rises 3m in 30 minutes (i. e., half an hour)


•°•°•°•°•°<><><<><>><><>°•°•°•°•°•°