Question

Water flows out through a circular pipe whose internal radius is 1 cm at the rate of 80cm/second into an empty cylinderical tank, the radius of whose base is 40 cm. By how much will the level of water rise in the tank in half an hour?

Answer 1

Answer : Height is 2.7 meters.

Step - by - step explanation :

Volume of water that flows from cylindrical pipe = πr²h

= 3.14 × 1² cm² × 80 cm/s

= 251.2 cm³/s

In Half an our, means 1½ hr or 3/2 hrs we get 1 hr = 60 × 60 s

= 3/2 × 60 × 60s = 3 × 30 × 60 s

= 5400 s

So, total time for which water flowed,

= 251.2 cm³/s × 5400 s

= 1356480 cm³

This volume of water is filled in a cylinderical tank,

1356480 cm³ = 3.14 × (40 cm)² × h

432000 cm³ = 1600 cm² × h

270 cm = height

In meters, 270 cm = 270/100 m = 2.7 m