Math, asked by delfinademarchi, 5 months ago

Water flows over the Browne Falls at a rate of 3680 litres per second. After rain, this rate increases to 9752 litres per second. Calculate the percentage increase in this rate.

Answers

Answered by rihan92
8

Answer:

165%.

Step-by-step explanation:

Actual increase in water flow/sec= 9752-3680=6072

So, the percentage of increase is [(6072÷3680)×100] =165

Answered by sangram0111
1

Given:

Water flows over the Browne Falls at a rate of 3680 litres per second. After rain, this rate increases to 9752 litres per second.

Solution:

Know that,

\[{\rm{Perentage}}\,{\rm{increase}} = \frac{{{\rm{Increased}}\,{\rm{value}} - {\rm{Initial}}\,{\rm{value}}}}{{{\rm{Initial}}\,{\rm{value}}}} \times 100\]

Therefore,

\[{\rm{Perentage}}\,{\rm{increase}} = \frac{{9752 - 3680}}{{3680}} \times 100\]

                            \[\begin{array}{l} = \frac{{6072}}{{3680}} \times 100\\ = \frac{{6072}}{{3680}} \times 100\\ = 1.65 \times 100\\ = 165\% \end{array}\]

Hence, the percentage increase in this rate is 165%.

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