Question

Water flows through a 100 mm diameter pipe with a velocity of 0.015 m/sec. If the kinematic viscosity of water is 1.13*10^-6 m^2 sec, the friction factor of the pipe material is

Answer 1

Answer:

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Answer 2

The friction factor of the pipe material  is 0.048.

Explanation:

Given that,

Diameter = 100 mm

Velocity = 0.015 m/s

Kinematic viscosity of water $\sigma=1.13\times10^{-6}\ m^2$

We need to calculate the Reynolds number

Using formula of Reynolds number

$R_{e}=\dfrac{\rho\times v\times d}{\sigma}$

Put the value into the formula

$R_{e}=\dfrac{100\times10^{-3}\times0.015}{1.13\times10^{-6}}$

$R_{e}=1327.4$

$R_{e}<2000$

We need to calculate the friction factor of the pipe material

Using formula of friction factor

$f=\dfrac{64}{R_{e}}$

Put the value into the formula

$f=\dfrac{64}{1327.4}$

$f=0.048$

Hence, The friction factor of the pipe material  is 0.048.

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Topic : friction factor

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