Water flows through a circular pipe whose internal diameter is 2 cm at the rate of 0.7 m/sec into a cylindrical tank, the radius of whose base is 40 cm. By how much will the level of water rise in the tank in half an hour.
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Step-by-step explanation:
volumetric flow rate of water in pipe =
(π/4)*0.02^2*0.7 = 2.2*(10^-4) m^3/sec
0.00022= volume of tank/time
0.00022 = (π*0.4^2*h)/1800
h= 0.396/(π*0.4^2)= 0.7875 m =78.75 cm
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