Water flows through a circular pipe whose internal diameter is 2 cm at the rate of 0.7m per second into a cylindrical tank the radius of whose base is 40 cm. By how much will the level of water in the tank use in half an hour?
Answers
some it will move in some time or some seconds
Answer:
Step-by-step explanation:
Water flows through a circular pipe whose internal diameter is 2 cm at the rate of 0.7 m/sec into a cylindrical tank, the radius of whose base is 40 cm. By how much will the level of water rise in the tank in half an hour.
Solution:
Given diameter of the circular pipe = 2 cm
So, the radius of the circular pipe = 2/2 = 1 cm
Height of the circular pipe = 0.7 m = 0.7 * 100 = 70 cm
Now, volume of the water flows in 1 second = πr2 h
= 3.142 * 12 * 70
= 3.142 * 70
Volume of the water flows in 1/2 hours = 3.142 * 70 * 30 * 60
Now, volume of the water flows = Volume of the cylinder
=> 3.142 * 70 * 30 * 60 = πr2 h
=> 3.142 * 70 * 30 * 60 = 3.142 * (40)2 h
=> 70 * 30 * 60 = 40 * 40 * h
=> h = (70 * 30 * 60)/(40 * 40)
=> h = (70 * 3 * 6)/(4 * 4)
=> h = 1260/16
=> h = 78.85 cm
So, the level of water rise in the tank in half an hour is 78.75 cm