Question

Water flows through a circular pipe whose internal radius is 1cm, at the rate of 80cm/sec into an empty cylindrical tank, the radius of whose base is 40cm. By how much, will the level of water rise in the tank in half an hour?


Please answer fast and
I will mark him/her as BRAINLIEST​

Answer 1

Answer:

Cylindrical Pipe:

r = 1cm

l in 1sec = 80cm

l in half an hour = 80 × 1800 ( half an hour = 30 min = 30 × 60sec)

Cylindrical Tank:

R = 40cm

Volume of water filled in Cyl. Tank in 30min = Volume of water flows through the cylindrical pipe in 30min

$\pi {r}^{2}1 h1 = \pi {r}^{2}2 h2$

40×40×H= 1×1×80×1800

H = (8×1800)/(40×40)

H = 9 cm

Therefore water raised in tank in half an hour is 9cm