Question

Water flows through a circular pipe with diameter 1 1/3 cm at the rate of 0.63 m/sec into a cylindrical tank, the radius of whose base is 0.2m. By hiw much will the level of water rise in a n hour?
(Step by step explanation is required)​

Answer 1

Answer:

Internal diameter of pipe=1

3

1

cm=

3

4

cm

Internal radius of pipe=

3×2

4

cm=

3

2

cm

flow rate=0.63m/s

radius of cylindrical base=0.2m=20cm

0.63m in 1 s.

In 1 hour⟶0.63×60×60=2268m=226800cm

volume of cylindrical tank=πr

2

h

volume of circular pipe=volume of tank

226800×π×

3

2

×

3

2

=π×20×20×h

h=

3×3×π×20×20

226800×π×2×2

h=253cm

h=2.52m

∴ Water level rise to 2.52m in 1 hour.