Water flows through a cylindrical pipe at a speed of 80 cm/s
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Answer:
Given , radius of tank , r1=40cm
Let hight of water level in tank in half an hour =h1
Also , given internal radius of cylindrical pipe, r2=1cm
and speed of water =80cm/s i.e., in 1 water flow = 80 cm
∴ In 30 (min) water flow =80×60×30=144000cm
According to the question,
Volume of water in cylindrical tank = Volume of water flow from the circular pipe in half an hour
⇒ πr21h1=πr22h2
⇒ 40×40×h1=1×1×144000
∴ h1=14400040×40=90 cm in half an hour.
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