Physics, asked by akhila8450, 11 months ago

Water flows through a cylindrical pipe at a speed of 80 cm/s

Answers

Answered by Anonymous
1

Answer:

Given , radius of tank , r1=40cm

Let hight of water level in tank in half an hour =h1

Also , given internal radius of cylindrical pipe, r2=1cm

and speed of water =80cm/s i.e., in 1 water flow = 80 cm

∴ In 30 (min) water flow =80×60×30=144000cm

According to the question,

Volume of water in cylindrical tank = Volume of water flow from the circular pipe in half an hour

⇒ πr21h1=πr22h2

⇒ 40×40×h1=1×1×144000

∴ h1=14400040×40=90 cm in half an hour.

Similar questions