Math, asked by Viratanmol, 1 year ago

Water flows through a cylindrical pipe of diameter 7cm. at 36km/hr. Calculate time in minutes it would take to fill a cylindrical tank of radius 35 cm and height 1m.



with proper working

Answers

Answered by vijeshmdt
51
36km/hr = 10m/s
volume of water flowing through the pipe in one second is
\pi \times {0.035}^{2} \times 10
where 0.035 is the radius of pipe in metre

volume of the cylindrical tank is
\pi \times (0.35)^{2} \times 1
therefore time taken to fill the tank in seconds is
 \frac{\pi \times 0.35 \times 0.35}{\pi \times 0.035 \times 0.035 \times 10}
that is 10 seconds
1/6 minutes
Answered by Anonymous
36

Radius of pipe = 7/2cm

Rate of water flow = 36 km/h

= 36 xx 5/18 m/s

= 10 m/s

= 10 x 100 cm/s.

= 1000 cm/s

Volume of water flowing in 1 second = πr²h

= π×7/2×7/2×1000cm³

= π x 7 x 7 x 250 cm3 ....(1)

Radius of tank (R) = 35 cm

Height of tank (H) = 1 m = 100 cm

∴ Volume of tank = πr2H

= π x 35 x 35 x 100 cm3 ...(2)

∴ Time taken to fill the tank =

 =  \frac{Volume  \:  \: of \:  \:  tank}{Volume \:  of  \:  \: water \:  \:  flowing \:  \:  in  \: 1 sec}

 =  \frac{\pi \times 35 \times 35 \times 100}{\pi \times 7 \times 7 \times 250}

 = 10 \: sec

 =  \frac{10}{60}  \: min

 =  \frac{1}{6}  \: min

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