Water flows through a cylindrical pipe of internal diameter 7cm at 5m/sec. Calculate the volume in litres, of water discharged by the pipe in one minute. Also calculate the time taken in minutes the pipe would take to fill an empty rectangular tank 4m*3m*2.31m
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Answered by
340
In one sec. length of water flow in pipe = 5 m
radius = 7/2 = 3.5 cm = 0.0035 m
volume of water flow per sec = π r² h = π(0.0035)² ×5
=192.5× 10^(-6) m³
volume of water discharged per min = 192.5× 10^(-6) m³×60
= 11.55×10^(-3) m³
= 0.01155 m³
=11.55 Liter
volume of tank = 4×3×2.31 = 27.72 m³
∵1m³ = 1000 Liter
volume of tank = 27720 Liter
time to fill the tank = 27720/11.55 = 2400 minutes
= 2400/60 = 40 hours
radius = 7/2 = 3.5 cm = 0.0035 m
volume of water flow per sec = π r² h = π(0.0035)² ×5
=192.5× 10^(-6) m³
volume of water discharged per min = 192.5× 10^(-6) m³×60
= 11.55×10^(-3) m³
= 0.01155 m³
=11.55 Liter
volume of tank = 4×3×2.31 = 27.72 m³
∵1m³ = 1000 Liter
volume of tank = 27720 Liter
time to fill the tank = 27720/11.55 = 2400 minutes
= 2400/60 = 40 hours
Answered by
41
Answer:
Step-by-step explanation:
Area of the Pope's exhaust tube= π×(7/2)² cm²
= 22/7 ×(49/4) cm²
= 11×7/2 cm²
=(11×7)/2×10000 m²
=77/20000 m²
Now, rate of flow= 5 m/s = 5×60 m/mints
So, required time = (4×3×2.31)/(77/2000) ×(5×60) m/mints
=24 mints
Answer 24 mints
Solution Magic of Math(MoM)
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