Question

Water flows through a cylindrical pipe of varying cross section. The velocity is 3.0 m/s at a point where the pipe diameter is 1.0 cm. At a point where the pipe diameter is 3.0 cm, the velocity is​

Answer 1

At 1st point, P1=1 cm of mercury

=0.01m of Hg.

=0.01×(13.6×103)×9.8Pa;

v1=0.35 m/s

At the second nd point,

p2=?

v2=0.65 m/s and

ρ=103hg/m3.

According to Bernoulli’s theorem,

p1+1/2(ρV12)=p2+1/2(ρV22)

or P2=P1+1/2(ρ(v22−v12))

=0.01×13.6×103×9.8–1/2×10

Answer 2

Answer:

REFER TO ATTACHMENT

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