Water flows through a horizontal pipe of radius 1 cm at a speed of 2 s^-1, what should be the diameter of its nozzle if the water is to come out at a speed of 10 m/s?
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the diameter of its nozzle if the water is to come out at a speed of 10 m/s water flows through a horizontal pipe of radius 1 cm at a speed of should be the diameter.
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Dear Student,
◆ Answer -
Diameter of nozzle = 0.8954 cm
● Explanation -
# Given -
r1 = 1 cm
v1 = 2 m/s
r2 = ?
v2 = 10 m/s
# Solution -
According to equation of continuity,
A1 × v1 = A2 × v2
πr1^2 × v1 = πr2^2 × v2
r1^2 × v1 = r2^2 × v2
r2^2 = v1/v2 × r1^2
r2 = r1 √(v1/v2)
r2 = 1 √(2/10)
r2 = 1/√5
r2 = 0.4472 cm
Diameter of nozzle is -
d = 2 × r2
d = 2 × 0.4472
d = 0.8954 cm
Thanks dear. Hope this helps you...
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