Question

Water flows through a horizontal pipe of radius 1 cm at a speed of 8 cm s^(-1). What will be the speed of flow of water under similar conditions, if the radius of the pipe is doubled ?

Answer 1

Explanation:

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Answer 2

Answer:

Explanation:

Dear Student,

◆ Answer -

Diameter of nozzle = 0.8954 cm

● Explanation -

# Given -

r1 = 1 cm

v1 = 2 m/s

r2 = ?

v2 = 10 m/s

# Solution -

According to equation of continuity,

A1 × v1 = A2 × v2

πr1^2 × v1 = πr2^2 × v2

r1^2 × v1 = r2^2 × v2

r2^2 = v1/v2 × r1^2

r2 = r1 √(v1/v2)

r2 = 1 √(2/10)

r2 = 1/√5

r2 = 0.4472 cm

Diameter of nozzle is -

d = 2 × r2

d = 2 × 0.4472

d = 0.8954 cm

Thanks dear. Hope this helps you...