Water flows through a horizontal pipeline of varying cross section at the rate of 20 liters per minute. Determine the velocity of water at a point where diameter is 4 CM.
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A₁v₁ = A₂v₂
A₁L/t = A₂v₂
Volume/time = A₂v₂. (v- velocity)
20/60 = π 4 X 10⁻² v₂
v₂ = 2.65 m/s
nancybansal680:
second step m 1/t kese aa gya
It's L /t. v = L/t
how is volume equal to length/time
its velocity
okk
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